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/*
* @lc app=leetcode id=706 lang=cpp
*
* [706] Design HashMap
*
* https://leetcode.com/problems/design-hashmap/description/
*
* algorithms
* Easy (65.22%)
* Likes: 3480
* Dislikes: 328
* Total Accepted: 361.2K
* Total Submissions: 554.4K
* Testcase Example: '["MyHashMap","put","put","get","get","put","get","remove","get"]\n' +
'[[],[1,1],[2,2],[1],[3],[2,1],[2],[2],[2]]'
*
* Design a HashMap without using any built-in hash table libraries.
*
* Implement the MyHashMap class:
*
*
* MyHashMap() initializes the object with an empty map.
* void put(int key, int value) inserts a (key, value) pair into the HashMap.
* If the key already exists in the map, update the corresponding value.
* int get(int key) returns the value to which the specified key is mapped, or
* -1 if this map contains no mapping for the key.
* void remove(key) removes the key and its corresponding value if the map
* contains the mapping for the key.
*
*
*
* Example 1:
*
*
* Input
* ["MyHashMap", "put", "put", "get", "get", "put", "get", "remove", "get"]
* [[], [1, 1], [2, 2], [1], [3], [2, 1], [2], [2], [2]]
* Output
* [null, null, null, 1, -1, null, 1, null, -1]
*
* Explanation
* MyHashMap myHashMap = new MyHashMap();
* myHashMap.put(1, 1); // The map is now [[1,1]]
* myHashMap.put(2, 2); // The map is now [[1,1], [2,2]]
* myHashMap.get(1); // return 1, The map is now [[1,1], [2,2]]
* myHashMap.get(3); // return -1 (i.e., not found), The map is now [[1,1],
* [2,2]]
* myHashMap.put(2, 1); // The map is now [[1,1], [2,1]] (i.e., update the
* existing value)
* myHashMap.get(2); // return 1, The map is now [[1,1], [2,1]]
* myHashMap.remove(2); // remove the mapping for 2, The map is now [[1,1]]
* myHashMap.get(2); // return -1 (i.e., not found), The map is now
* [[1,1]]
*
*
*
* Constraints:
*
*
* 0 <= key, value <= 10^6
* At most 10^4 calls will be made to put, get, and remove.
*
*
*/
// @lc code=start
class MyHashMap
{
private:
vector<unsigned int> *map;
public:
MyHashMap() : map(new vector<unsigned int>(1000001, -1)) {}
void put(int key, int value) { (*map)[key] = value; }
int get(int key) { return (*map)[key]; }
void remove(int key) { (*map)[key] = -1; }
};
/**
* Your MyHashMap object will be instantiated and called as such:
* MyHashMap* obj = new MyHashMap();
* obj->put(key,value);
* int param_2 = obj->get(key);
* obj->remove(key);
*/
// @lc code=end